#include stdio.h main int k 1 j 0 while k+j 4
WebMar 13, 2024 · 以下是用 C 语言实现的代码示例: ``` #include #include int main() { char s[] = "hello"; // 定义字符串 s int t[26] = {0}; // 定义数组 t,初始化为 0 int len = strlen(s); // 获取字符串 s 的长度 for (int i = 0; i < len; i++) { // 将字符转化为下标值 int index = s[i] - 'a'; t[index ...
#include stdio.h main int k 1 j 0 while k+j 4
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WebApr 4, 2024 · 1 Base64编码概述 Base64是一种编码方式,这个术语最初是在“MIME内容传输编码规范”中提出的。Base64不是一种加密算法,它实际上是一种“二进制转换到文本”的 … WebSep 6, 2024 · 4. 1 The answer is option (2). Explanation: Here k is floating-point variable and we can’t apply % operator in floating-point variable.The modulo operator % in C and C++ is …
Web#define N 20 main() { int i,a[N]; for(i=0;i WebExpert Answer. All the given programs are run in a c compiler and the outputs are shown below as proof. Program 1: The answer is option b. herehereherehere Proof: Explanation: Whi …. View the full answer. Transcribed image text: #include int main () { int i = 4; while (i) { printf ("here"); } return 0; } O a. here D O b ...
WebAug 21, 2011 · Sorted by: 1. In you inset function, change arr [size]=arr [size-1]; to arr [size-j]=arr [size-j-1];. When you do the insertion, I guess you wanted to shift all the numbers … WebJan 20, 2024 · #include int main () { int c = 5, no = 1000; do { no /= c; } while(c--); printf ("%d\n", no); return 0; } Output: Exception – Divide by zero Explanation: There is a …
WebApr 10, 2024 · 方法一: #include #include #include #include
WebStep 1: int i=4, j=-1, k=0, w, x, y, z; here variable i, j, k, w, x, y, z are declared as an integer type and the variable i, j, k are initialized to 4, -1, 0 respectively. Step 2: w = i j k; becomes w … imam thabraniWeb2 days ago · 4.2 演示示例 # include # include # include int main {// 初始化种子 srand48 (time (NULL)); // 生成10个随机数 for (int i = 0; i < 5; ++ i) {double r = jrand48 (); printf ("%f\n", r);} return 0;} 上述程序首先通过 srand48 函数初始化随机数生成器的种子,这里使用了当前系统 ... list of graffiti artistsWebnow j = i++ <= 1; ie) j = 1 <= 1; ie) i = 2 for the every next line. Now the control goes to the increment part and prints 2 1 still the condition in for loop is 1 again it comes to j = i++ <= 1; j = 2 <= 1; here the condition is false and set j = 0; Now the control goes to the increment part and prints 3 0 Now the condition in for loop is 0 ... imam tawhidi twitterWebIn an expression involving operator, evaluation takes place from left to right and will be stopped if one of its components evaluates to true (a non zero value). So in the given … list of graduation songs for high schoolWebDec 10, 2024 · 1 Once you ignore the for loops, the rest becomes: int main () { int i,j,count; count=0; { { count++; } } printf ("%d",count); return 0; } So you may see the counter is getting incremented once. Share Improve this answer Follow … list of graduation honorsWeb#include int main() { void fun(int, int[]); int arr[] = {1, 2, 3, 4}; int i; fun(4, arr); for(i=0; i<4; i++) printf("%d,", arr[i]); return 0; } void fun(int n, int arr[]) { int *p=0; int i=0; while(i++ < n) p = &arr[i]; *p=0; } 2, 3, 4, 5 1, 2, 3, 4 0, 1, 2, 3 3, 2, 1 0 4. What will be the output of the program ? imam tawhidi factsWeb341. Which of the statements is correct about the program? #include int main () { int i = 10 ; int * j = & i; return 0 ; } a. j and i are pointers to an int. b. i is a pointer to an int and stores address of j. c. j is a pointer to an int and stores address of i. imam talib shareef washington dc